What is x^2+y^2+6x-8y+13=0 ?

The solution to x^2+y^2+6x-8y+13=0 is Circle with (a,b)=(-3,4),r=2sqrt(3)

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x^2+y^2+6x-8y+13=0

x^{2} + y^{2} + 6 x - 8 y + 13 = 0

(a, b) = (- 3, 4), r = 23

Solution steps

x^{2} + y^{2} + 6 x - 8 y + 13 = 0

Rewrite

x^{2} + y^{2} + 6 x - 8 y + 13 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 4)^{2} = (23)^{2}

Therefore the circle properties are:

(a, b) = (- 3, 4), r = 23

(x + 4)^{2} + (y - 5)^{2} = 4

4 x^{2} + 4 y^{2} - 16 x + 24 y - 12 = 0

x^{2} - 6 x + y^{2} - 20 y + 44 = 0

x^{2} + y^{2} + 5 x - y - 2 = 0

x^{2} + y^{2} - 8 x - 20 y + 52 = 0

What is x^2+y^2+6x-8y+13=0 ?
The solution to x^2+y^2+6x-8y+13=0 is Circle with (a,b)=(-3,4),r=2sqrt(3)