What is x^2+y^2+5x-y-2=0 ?

The solution to x^2+y^2+5x-y-2=0 is Circle with (a,b)=(-5/2 , 1/2),r=sqrt(17/2)

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x^2+y^2+5x-y-2=0

x^{2} + y^{2} + 5 x - y - 2 = 0

(a, b) = (- \frac{5}{2}, \frac{1}{2}), r = \frac{17}{2}

Solution steps

x^{2} + y^{2} + 5 x - y - 2 = 0

Rewrite

x^{2} + y^{2} + 5 x - y - 2 = 0

in the form of the standard circle equation

(x - (- \frac{5}{2}))^{2} + (y - \frac{1}{2})^{2} = (\frac{17}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{5}{2}, \frac{1}{2}), r = \frac{17}{2}

x^{2} + y^{2} - 8 x - 20 y + 52 = 0

(x)^{2} + (y)^{2} = 1

(x - 2)^{2} + (y - 1)^{2} = 49

y^{2} + x^{2} \leq 1

x^{2} + y^{2} - 6 x - 8 y - 14 = 0

What is x^2+y^2+5x-y-2=0 ?
The solution to x^2+y^2+5x-y-2=0 is Circle with (a,b)=(-5/2 , 1/2),r=sqrt(17/2)