What is (x)^2+(y)^2=1 ?

The solution to (x)^2+(y)^2=1 is Circle with (a,b)=(0,0),r=1

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(x)^2+(y)^2=1

(x)^{2} + (y)^{2} = 1

(a, b) = (0, 0), r = 1

Solution steps

x^{2} + y^{2} = 1

Rewrite

x^{2} + y^{2} = 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 1

(x - 2)^{2} + (y - 1)^{2} = 49

y^{2} + x^{2} \leq 1

x^{2} + y^{2} - 6 x - 8 y - 14 = 0

x^{2} + y^{2} + 10 x + 12 y - 3 = 0

x^{2} + y^{2} - 6 x - 4 y - 7 = 0

What is (x)^2+(y)^2=1 ?
The solution to (x)^2+(y)^2=1 is Circle with (a,b)=(0,0),r=1