What is x^2-2x+y^2+2y=102 ?

The solution to x^2-2x+y^2+2y=102 is Circle with (a,b)=(1,-1),r=2sqrt(26)

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x^2-2x+y^2+2y=102

x^{2} - 2 x + y^{2} + 2 y = 102

(a, b) = (1, - 1), r = 226

Solution steps

x^{2} - 2 x + y^{2} + 2 y = 102

Rewrite

x^{2} - 2 x + y^{2} + 2 y = 102

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 1))^{2} = (226)^{2}

Therefore the circle properties are:

(a, b) = (1, - 1), r = 226

3. 6^{2} = (x + 0.001)^{2} + (y + 0.3)^{2}

x^{2} + y^{2} \geq 25

(x - 512)^{2} + y^{2} = 256

x^{2} + y^{2} - x - 6 y + \frac{1}{4} = 0

x^{2} + y^{2} + 6 x - 8 y + 21 = 0

What is x^2-2x+y^2+2y=102 ?
The solution to x^2-2x+y^2+2y=102 is Circle with (a,b)=(1,-1),r=2sqrt(26)