What is y^2+x^2-8x+18y+72=0 ?

The solution to y^2+x^2-8x+18y+72=0 is Circle with (a,b)=(4,-9),r=5

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y^2+x^2-8x+18y+72=0

y^{2} + x^{2} - 8 x + 18 y + 72 = 0

(a, b) = (4, - 9), r = 5

Solution steps

y^{2} + x^{2} - 8 x + 18 y + 72 = 0

Rewrite

y^{2} + x^{2} - 8 x + 18 y + 72 = 0

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 9))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (4, - 9), r = 5

x^{2} + y^{2} + 8 x + 4 y + 19 = 0

4 x^{2} + 4 x + 4 y^{2} + 4 y - 2 = 0

x^{2} + 2 x + y^{2} - 2 y = - 1

x^{2} + y^{2} + 10 x - 23 = 0

(X - 4)^{2} + (Y + 9)^{2} = 2

What is y^2+x^2-8x+18y+72=0 ?
The solution to y^2+x^2-8x+18y+72=0 is Circle with (a,b)=(4,-9),r=5