What is x^2+y^2-2x+14y+34=0 ?

The solution to x^2+y^2-2x+14y+34=0 is Circle with (a,b)=(1,-7),r=4

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x^2+y^2-2x+14y+34=0

x^{2} + y^{2} - 2 x + 14 y + 34 = 0

(a, b) = (1, - 7), r = 4

Solution steps

x^{2} + y^{2} - 2 x + 14 y + 34 = 0

Rewrite

x^{2} + y^{2} - 2 x + 14 y + 34 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 7))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, - 7), r = 4

x^{2} - 2 x + 1 + y^{2} + y - \frac{4}{4} = \frac{11}{4}

(x - 5)^{2} + (y + 7)^{2} = 4

(x - 1)^{2} + (y - (- \frac{1}{2}))^{2} = 2^{2}

x^{2} + y^{2} = 2 3^{2}

- 2 = x^{2} + y^{2} - 6 x + 5

What is x^2+y^2-2x+14y+34=0 ?
The solution to x^2+y^2-2x+14y+34=0 is Circle with (a,b)=(1,-7),r=4