What is x^2-2x+1+y^2+y-4/4 = 11/4 ?

The solution to x^2-2x+1+y^2+y-4/4 = 11/4 is Circle with (a,b)=(1,-1/2),r=2

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x^2-2x+1+y^2+y-4/4 = 11/4

x^{2} - 2 x + 1 + y^{2} + y - \frac{4}{4} = \frac{11}{4}

(a, b) = (1, - \frac{1}{2}), r = 2

Solution steps

x^{2} - 2 x + 1 + y^{2} + y - \frac{4}{4} = \frac{11}{4}

Rewrite

x^{2} - 2 x + 1 + y^{2} + y - \frac{4}{4} = \frac{11}{4}

in the form of the standard circle equation

(x - 1)^{2} + (y - (- \frac{1}{2}))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (1, - \frac{1}{2}), r = 2

(x - 5)^{2} + (y + 7)^{2} = 4

(x - 1)^{2} + (y - (- \frac{1}{2}))^{2} = 2^{2}

x^{2} + y^{2} = 2 3^{2}

- 2 = x^{2} + y^{2} - 6 x + 5

x^{2} + y^{2} - 4 x - 6 x + 9 = 0

What is x^2-2x+1+y^2+y-4/4 = 11/4 ?
The solution to x^2-2x+1+y^2+y-4/4 = 11/4 is Circle with (a,b)=(1,-1/2),r=2