What is (x-1)^2+(y-(-1/2))^2=2^2 ?

The solution to (x-1)^2+(y-(-1/2))^2=2^2 is Circle with (a,b)=(1,-1/2),r=2

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(x-1)^2+(y-(-1/2))^2=2^2

(x - 1)^{2} + (y - (- \frac{1}{2}))^{2} = 2^{2}

(a, b) = (1, - \frac{1}{2}), r = 2

Solution steps

(x - 1)^{2} + (y - (- \frac{1}{2}))^{2} = 2^{2}

Rewrite

(x - 1)^{2} + (y - (- \frac{1}{2}))^{2} = 2^{2}

in the form of the standard circle equation

(x - 1)^{2} + (y - (- \frac{1}{2}))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (1, - \frac{1}{2}), r = 2

x^{2} + y^{2} = 2 3^{2}

- 2 = x^{2} + y^{2} - 6 x + 5

x^{2} + y^{2} - 4 x - 6 x + 9 = 0

x^{2} + y^{2} + 2 x + 4 y - 12 = 0

a^{2} + b^{2} = a - b

What is (x-1)^2+(y-(-1/2))^2=2^2 ?
The solution to (x-1)^2+(y-(-1/2))^2=2^2 is Circle with (a,b)=(1,-1/2),r=2