What is x^2+y^2-4x-6x+9=0 ?

The solution to x^2+y^2-4x-6x+9=0 is Circle with (a,b)=(5,0),r=4

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x^2+y^2-4x-6x+9=0

x^{2} + y^{2} - 4 x - 6 x + 9 = 0

(a, b) = (5, 0), r = 4

Solution steps

x^{2} + y^{2} - 4 x - 6 x + 9 = 0

Rewrite

x^{2} + y^{2} - 4 x - 6 x + 9 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (5, 0), r = 4

x^{2} + y^{2} + 2 x + 4 y - 12 = 0

a^{2} + b^{2} = a - b

(x - 6)^{2} + (y - 10)^{2} = 5^{2}

x^{2} + y^{2} - 4 x + 2 y - 76 = 0

x^{2} + y^{2} + 6 x + 2 y - 15 = 0

What is x^2+y^2-4x-6x+9=0 ?
The solution to x^2+y^2-4x-6x+9=0 is Circle with (a,b)=(5,0),r=4