What is a^2+b^2=a-b ?

The solution to a^2+b^2=a-b is Circle with (a,b)=(1/2 ,-1/2),r=sqrt(1/2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

a^2+b^2=a-b

a^{2} + b^{2} = a - b

(a, b) = (\frac{1}{2}, - \frac{1}{2}), r = \frac{1}{2}

Solution steps

a^{2} + b^{2} = a - b

Rewrite

a^{2} + b^{2} = a - b

in the form of the standard circle equation

(a - \frac{1}{2})^{2} + (b - (- \frac{1}{2}))^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, - \frac{1}{2}), r = \frac{1}{2}

(x - 6)^{2} + (y - 10)^{2} = 5^{2}

x^{2} + y^{2} - 4 x + 2 y - 76 = 0

x^{2} + y^{2} + 6 x + 2 y - 15 = 0

x^{2} + y^{2} + 12 \cdot (- 4) y + 4 = 0

x^{2} - 4 x + 4 + y^{2} - 2 y + 1 = 9

What is a^2+b^2=a-b ?
The solution to a^2+b^2=a-b is Circle with (a,b)=(1/2 ,-1/2),r=sqrt(1/2)