What is x^2-4x+4+y^2-2y+1=9 ?

The solution to x^2-4x+4+y^2-2y+1=9 is Circle with (a,b)=(2,1),r=3

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x^2-4x+4+y^2-2y+1=9

x^{2} - 4 x + 4 + y^{2} - 2 y + 1 = 9

(a, b) = (2, 1), r = 3

Solution steps

x^{2} - 4 x + 4 + y^{2} - 2 y + 1 = 9

Rewrite

x^{2} - 4 x + 4 + y^{2} - 2 y + 1 = 9

in the form of the standard circle equation

(x - 2)^{2} + (y - 1)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (2, 1), r = 3

- 2 x^{2} - 2 y^{2} + 4 x - 16 y + 2 = 0

x^{2} + y^{2} - 10 x - 2 y - 74 = 0

9 x^{2} + 9 y^{2} + 12 y + 36 y - 104 = 0

4 x^{2} + 4 y^{2} - 32 y + 39 = 0

x^{2} + 12 x + y^{2} - 12 y = - 56

What is x^2-4x+4+y^2-2y+1=9 ?
The solution to x^2-4x+4+y^2-2y+1=9 is Circle with (a,b)=(2,1),r=3