What is (x-4)^2+(y+11)^2=25 ?

The solution to (x-4)^2+(y+11)^2=25 is Circle with (a,b)=(4,-11),r=5

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(x-4)^2+(y+11)^2=25

(x - 4)^{2} + (y + 11)^{2} = 25

(a, b) = (4, - 11), r = 5

Solution steps

(x - 4)^{2} + (y + 11)^{2} = 25

Rewrite

(x - 4)^{2} + (y + 11)^{2} = 25

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 11))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (4, - 11), r = 5

x^{2} + y^{2} - 3 = 1

(x^{2} - 2 x) + (y^{2} + 4 y) = - 2

x^{2} + y^{2} + 2 x - 244 = 0

(x - 3)^{2} + y^{2} < 4

3 x^{2} + 3 y^{2} + 36 x - 24 y + 96 = 0

What is (x-4)^2+(y+11)^2=25 ?
The solution to (x-4)^2+(y+11)^2=25 is Circle with (a,b)=(4,-11),r=5