What is 3x^2+3y^2+36x-24y+96=0 ?

The solution to 3x^2+3y^2+36x-24y+96=0 is Circle with (a,b)=(-6,4),r=2sqrt(5)

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3x^2+3y^2+36x-24y+96=0

3 x^{2} + 3 y^{2} + 36 x - 24 y + 96 = 0

(a, b) = (- 6, 4), r = 25

Solution steps

3 x^{2} + 3 y^{2} + 36 x - 24 y + 96 = 0

Rewrite

3 x^{2} + 3 y^{2} + 36 x - 24 y + 96 = 0

in the form of the standard circle equation

(x - (- 6))^{2} + (y - 4)^{2} = (25)^{2}

Therefore the circle properties are:

(a, b) = (- 6, 4), r = 25

x^{2} + y^{2} - 20 x - 14 y + 100 = 0

(x - 4)^{2} + (Y (x) + 2)^{2} = 4

x^{2} + y^{2} - 4 x + 8 y = - 4

\frac{x ^{2}}{2} + \frac{y ^{2}}{2} + 112. 6^{2} = 180. 3^{2}

x^{2} + y^{2} = 5200

What is 3x^2+3y^2+36x-24y+96=0 ?
The solution to 3x^2+3y^2+36x-24y+96=0 is Circle with (a,b)=(-6,4),r=2sqrt(5)