What is x^2+y^2+2x-244=0 ?

The solution to x^2+y^2+2x-244=0 is Circle with (a,b)=(-1,0),r=7sqrt(5)

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x^2+y^2+2x-244=0

x^{2} + y^{2} + 2 x - 244 = 0

(a, b) = (- 1, 0), r = 75

Solution steps

x^{2} + y^{2} + 2 x - 244 = 0

Rewrite

x^{2} + y^{2} + 2 x - 244 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 0)^{2} = (75)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 0), r = 75

(x - 3)^{2} + y^{2} < 4

3 x^{2} + 3 y^{2} + 36 x - 24 y + 96 = 0

x^{2} + y^{2} - 20 x - 14 y + 100 = 0

(x - 4)^{2} + (Y (x) + 2)^{2} = 4

x^{2} + y^{2} - 4 x + 8 y = - 4

What is x^2+y^2+2x-244=0 ?
The solution to x^2+y^2+2x-244=0 is Circle with (a,b)=(-1,0),r=7sqrt(5)