What is x^2+y^2-4x+8y=-4 ?

The solution to x^2+y^2-4x+8y=-4 is Circle with (a,b)=(2,-4),r=4

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x^2+y^2-4x+8y=-4

x^{2} + y^{2} - 4 x + 8 y = - 4

(a, b) = (2, - 4), r = 4

Solution steps

x^{2} + y^{2} - 4 x + 8 y = - 4

Rewrite

x^{2} + y^{2} - 4 x + 8 y = - 4

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 4))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (2, - 4), r = 4

\frac{x ^{2}}{2} + \frac{y ^{2}}{2} + 112. 6^{2} = 180. 3^{2}

x^{2} + y^{2} = 5200

y^{2} + x^{2} = 160

(x + 2)^{2} + (y - \frac{3}{2})^{2} = \frac{25}{4}

(x - 2)^{2} + [y - (- 3)]^{2} = (3)^{2}

What is x^2+y^2-4x+8y=-4 ?
The solution to x^2+y^2-4x+8y=-4 is Circle with (a,b)=(2,-4),r=4