What is y^2+x^2=160 ?

The solution to y^2+x^2=160 is Circle with (a,b)=(0,0),r=sqrt(160)

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y^2+x^2=160

y^{2} + x^{2} = 160

(a, b) = (0, 0), r = 160

Solution steps

y^{2} + x^{2} = 160

Rewrite

y^{2} + x^{2} = 160

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (160)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 160

(x + 2)^{2} + (y - \frac{3}{2})^{2} = \frac{25}{4}

(x - 2)^{2} + [y - (- 3)]^{2} = (3)^{2}

(x \cdot 1)^{2} + (y - 1)^{2} = 5

\frac{x ^{2}}{2} + \frac{y ^{2}}{2} = 18

a^{2} + b^{2} = a + 2

What is y^2+x^2=160 ?
The solution to y^2+x^2=160 is Circle with (a,b)=(0,0),r=sqrt(160)