What is (x+2)^2+(y-3/2)^2= 25/4 ?

The solution to (x+2)^2+(y-3/2)^2= 25/4 is Circle with (a,b)=(-2, 3/2),r= 5/2

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(x+2)^2+(y-3/2)^2= 25/4

(x + 2)^{2} + (y - \frac{3}{2})^{2} = \frac{25}{4}

(a, b) = (- 2, \frac{3}{2}), r = \frac{5}{2}

Solution steps

(x + 2)^{2} + (y - \frac{3}{2})^{2} = \frac{25}{4}

Rewrite

(x + 2)^{2} + (y - \frac{3}{2})^{2} = \frac{25}{4}

in the form of the standard circle equation

(x - (- 2))^{2} + (y - \frac{3}{2})^{2} = (\frac{5}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 2, \frac{3}{2}), r = \frac{5}{2}

(x - 2)^{2} + [y - (- 3)]^{2} = (3)^{2}

(x \cdot 1)^{2} + (y - 1)^{2} = 5

\frac{x ^{2}}{2} + \frac{y ^{2}}{2} = 18

a^{2} + b^{2} = a + 2

x^{2} + y^{2} - 8 x - 6 y - 16 = 0

What is (x+2)^2+(y-3/2)^2= 25/4 ?
The solution to (x+2)^2+(y-3/2)^2= 25/4 is Circle with (a,b)=(-2, 3/2),r= 5/2