What is (x^2)/2+(y^2)/2 =18 ?

The solution to (x^2)/2+(y^2)/2 =18 is Circle with (a,b)=(0,0),r=6

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(x^2)/2+(y^2)/2 =18

\frac{x ^{2}}{2} + \frac{y ^{2}}{2} = 18

(a, b) = (0, 0), r = 6

Solution steps

\frac{x ^{2}}{2} + \frac{y ^{2}}{2} = 18

Rewrite

\frac{x ^{2}}{2} + \frac{y ^{2}}{2} = 18

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 6

a^{2} + b^{2} = a + 2

x^{2} + y^{2} - 8 x - 6 y - 16 = 0

8 - 9 (x^{2} + y^{2}) = 9 (x^{2} + y^{2})

a^{2} + b^{2} + 0.02 = 1

x^{2} + y^{2} + 4 x + 0 y + 3 = 0

What is (x^2)/2+(y^2)/2 =18 ?
The solution to (x^2)/2+(y^2)/2 =18 is Circle with (a,b)=(0,0),r=6