What is x^2+y^2-8x-6y-16=0 ?

The solution to x^2+y^2-8x-6y-16=0 is Circle with (a,b)=(4,3),r=sqrt(41)

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x^2+y^2-8x-6y-16=0

x^{2} + y^{2} - 8 x - 6 y - 16 = 0

(a, b) = (4, 3), r = 41

Solution steps

x^{2} + y^{2} - 8 x - 6 y - 16 = 0

Rewrite

x^{2} + y^{2} - 8 x - 6 y - 16 = 0

in the form of the standard circle equation

(x - 4)^{2} + (y - 3)^{2} = (41)^{2}

Therefore the circle properties are:

(a, b) = (4, 3), r = 41

8 - 9 (x^{2} + y^{2}) = 9 (x^{2} + y^{2})

a^{2} + b^{2} + 0.02 = 1

x^{2} + y^{2} + 4 x + 0 y + 3 = 0

(x - 3)^{2} + y^{2} = 3

(x - 3)^{2} + y^{2} = 6

What is x^2+y^2-8x-6y-16=0 ?
The solution to x^2+y^2-8x-6y-16=0 is Circle with (a,b)=(4,3),r=sqrt(41)