What is 3x^2+3y^2-12x-15y-6=0 ?

The solution to 3x^2+3y^2-12x-15y-6=0 is Circle with (a,b)=(2, 5/2),r= 7/2

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3x^2+3y^2-12x-15y-6=0

3 x^{2} + 3 y^{2} - 12 x - 15 y - 6 = 0

(a, b) = (2, \frac{5}{2}), r = \frac{7}{2}

Solution steps

3 x^{2} + 3 y^{2} - 12 x - 15 y - 6 = 0

Rewrite

3 x^{2} + 3 y^{2} - 12 x - 15 y - 6 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - \frac{5}{2})^{2} = (\frac{7}{2})^{2}

Therefore the circle properties are:

(a, b) = (2, \frac{5}{2}), r = \frac{7}{2}

x^{2} + y^{2} - \frac{27}{8} x + \frac{31}{8} y - \frac{39}{8} = 0

x^{2} + y^{2} + 8 x - 12 y = 0

x^{2} + y^{2} \leq 12

x^{2} + y^{2} + 4 x + 28 y + 175 = 0

3 x^{2} + 3 y^{2} - 18 x - 12 y + 12 = 0

What is 3x^2+3y^2-12x-15y-6=0 ?
The solution to 3x^2+3y^2-12x-15y-6=0 is Circle with (a,b)=(2, 5/2),r= 7/2