What is x^2+y^2+8x-12y=0 ?

The solution to x^2+y^2+8x-12y=0 is Circle with (a,b)=(-4,6),r=2sqrt(13)

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x^2+y^2+8x-12y=0

x^{2} + y^{2} + 8 x - 12 y = 0

(a, b) = (- 4, 6), r = 213

Solution steps

x^{2} + y^{2} + 8 x - 12 y = 0

Rewrite

x^{2} + y^{2} + 8 x - 12 y = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 6)^{2} = (213)^{2}

Therefore the circle properties are:

(a, b) = (- 4, 6), r = 213

x^{2} + y^{2} \leq 12

x^{2} + y^{2} + 4 x + 28 y + 175 = 0

3 x^{2} + 3 y^{2} - 18 x - 12 y + 12 = 0

(x + 4)^{2} + (y - 6)^{2} = \frac{6}{2}

xx + y^{2} = 5

What is x^2+y^2+8x-12y=0 ?
The solution to x^2+y^2+8x-12y=0 is Circle with (a,b)=(-4,6),r=2sqrt(13)