What is x^2+y^2+4x+28y+175=0 ?

The solution to x^2+y^2+4x+28y+175=0 is Circle with (a,b)=(-2,-14),r=5

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x^2+y^2+4x+28y+175=0

x^{2} + y^{2} + 4 x + 28 y + 175 = 0

(a, b) = (- 2, - 14), r = 5

Solution steps

x^{2} + y^{2} + 4 x + 28 y + 175 = 0

Rewrite

x^{2} + y^{2} + 4 x + 28 y + 175 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 14))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 14), r = 5

3 x^{2} + 3 y^{2} - 18 x - 12 y + 12 = 0

(x + 4)^{2} + (y - 6)^{2} = \frac{6}{2}

xx + y^{2} = 5

(x - 0)^{2} + (y - 1)^{2} = 1

(x - \frac{3}{5})^{2} + (y + \frac{7}{8})^{2} = \frac{9}{4}

What is x^2+y^2+4x+28y+175=0 ?
The solution to x^2+y^2+4x+28y+175=0 is Circle with (a,b)=(-2,-14),r=5