What is 4=x^2+y^2-2x+4y ?

The solution to 4=x^2+y^2-2x+4y is Circle with (a,b)=(1,-2),r=3

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4=x^2+y^2-2x+4y

4 = x^{2} + y^{2} - 2 x + 4 y

(a, b) = (1, - 2), r = 3

Solution steps

4 = x^{2} + y^{2} - 2 x + 4 y

Rewrite

4 = x^{2} + y^{2} - 2 x + 4 y

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 2))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (1, - 2), r = 3

(x - 12)^{2} + (y + 7)^{2} = 961

(x + 4)^{2} + (y + 1)^{2} = 100

(x - 8)^{2} + (y - 6)^{2} = 1^{2}

x^{2} + (y - \frac{25}{3})^{2} = 144

\frac{x ^{2}}{15} + \frac{y ^{2}}{15} - \frac{2 x}{15} - \frac{6}{15} = 0

What is 4=x^2+y^2-2x+4y ?
The solution to 4=x^2+y^2-2x+4y is Circle with (a,b)=(1,-2),r=3