What is (x-1)^2+((y-3)^2)/1 =4 ?

The solution to (x-1)^2+((y-3)^2)/1 =4 is Circle with (a,b)=(1,3),r=2

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(x-1)^2+((y-3)^2)/1 =4

(x - 1)^{2} + \frac{( y - 3 ) ^{2}}{1} = 4

(a, b) = (1, 3), r = 2

Solution steps

(x - 1)^{2} + \frac{( y - 3 ) ^{2}}{1} = 4

Rewrite

(x - 1)^{2} + \frac{( y - 3 ) ^{2}}{1} = 4

in the form of the standard circle equation

(x - 1)^{2} + (y - 3)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (1, 3), r = 2

(x - 4)^{2} + (y + 3)^{2} = 5

x^{2} + z^{2} = 36

(x + 1.6)^{2} + (y + 9.8)^{2} = 26

(x - 3)^{2} + (y - 1)^{2} = 20

\frac{x ^{2}}{2 ^{2}} + \frac{y ^{2}}{2 ^{2}} = 1

What is (x-1)^2+((y-3)^2)/1 =4 ?
The solution to (x-1)^2+((y-3)^2)/1 =4 is Circle with (a,b)=(1,3),r=2