What is (x+1.6)^2+(y+9.8)^2=26 ?

The solution to (x+1.6)^2+(y+9.8)^2=26 is Circle with (a,b)=(-1.6,-9.8),r=sqrt(26)

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(x+1.6)^2+(y+9.8)^2=26

(x + 1.6)^{2} + (y + 9.8)^{2} = 26

(a, b) = (- 1.6, - 9.8), r = 26

Solution steps

(x + 1.6)^{2} + (y + 9.8)^{2} = 26

Rewrite

(x + 1.6)^{2} + (y + 9.8)^{2} = 26

in the form of the standard circle equation

(x - (- 1.6))^{2} + (y - (- 9.8))^{2} = (26)^{2}

Therefore the circle properties are:

(a, b) = (- 1.6, - 9.8), r = 26

(x - 3)^{2} + (y - 1)^{2} = 20

\frac{x ^{2}}{2 ^{2}} + \frac{y ^{2}}{2 ^{2}} = 1

x^{2} + y^{2} + 10 x + 20 y + 77 = 0

(x - (- 3))^{2} + (y - 5)^{2} = 4

y^{2} = - x^{2} + 100

What is (x+1.6)^2+(y+9.8)^2=26 ?
The solution to (x+1.6)^2+(y+9.8)^2=26 is Circle with (a,b)=(-1.6,-9.8),r=sqrt(26)