What is 2x^2+2y^2-16y+24=0 ?

The solution to 2x^2+2y^2-16y+24=0 is Circle with (a,b)=(0,4),r=2

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2x^2+2y^2-16y+24=0

2 x^{2} + 2 y^{2} - 16 y + 24 = 0

(a, b) = (0, 4), r = 2

Solution steps

2 x^{2} + 2 y^{2} - 16 y + 24 = 0

Rewrite

2 x^{2} + 2 y^{2} - 16 y + 24 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 4)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 4), r = 2

x^{2} + y^{2} - x = 2

(x - 4)^{(2)} + (y + 10)^{(2)} = 144

x^{2} + 6 x + 9 + y^{2} - 2 y + 1 = 54 + 9 + 1

x^{2} = - y^{2} + 10 y + 5

(x - (- 4))^{2} + (y - (2))^{2} = 3^{2}

What is 2x^2+2y^2-16y+24=0 ?
The solution to 2x^2+2y^2-16y+24=0 is Circle with (a,b)=(0,4),r=2