What is x^2+y^2-3x=15-6y ?

The solution to x^2+y^2-3x=15-6y is Circle with (a,b)=(3/2 ,-3),r=(sqrt(105))/2

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x^2+y^2-3x=15-6y

x^{2} + y^{2} - 3 x = 15 - 6 y

(a, b) = (\frac{3}{2}, - 3), r = \frac{105}{2}

Solution steps

x^{2} + y^{2} - 3 x = 15 - 6 y

Rewrite

x^{2} + y^{2} - 3 x = 15 - 6 y

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - (- 3))^{2} = (\frac{105}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, - 3), r = \frac{105}{2}

2 x^{2} + x + 2 y^{2} = 6

z^{2} = 1 - y^{2}

(x - 9)^{2} + y^{2} = 2

(x + 2)^{2} + (y - 1.5)^{2} = (2.75 i)^{2}

2 x^{2} + 2 y^{2} = 100

What is x^2+y^2-3x=15-6y ?
The solution to x^2+y^2-3x=15-6y is Circle with (a,b)=(3/2 ,-3),r=(sqrt(105))/2