What is (x+0)^2+(y+0)^2=17 ?

The solution to (x+0)^2+(y+0)^2=17 is Circle with (a,b)=(0,0),r=sqrt(17)

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(x+0)^2+(y+0)^2=17

(x + 0)^{2} + (y + 0)^{2} = 17

(a, b) = (0, 0), r = 17

Solution steps

(x + 0)^{2} + (y + 0)^{2} = 17

Rewrite

(x + 0)^{2} + (y + 0)^{2} = 17

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (17)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 17

(x - 15)^{2} + (y + 7)^{2} = 1 5^{2}

x^{2} + y^{2} + 6 x + 8 y - 11 = 0

x^{2} + y^{2} + 6 x = 16

x^{(2)} + y^{(2)} + 25 x + 10 y = - 12

x^{2} + y^{2} + 14 x - 20 y + 100 = 0

What is (x+0)^2+(y+0)^2=17 ?
The solution to (x+0)^2+(y+0)^2=17 is Circle with (a,b)=(0,0),r=sqrt(17)