What is (x-15)^2+(y+7)^2=15^2 ?

The solution to (x-15)^2+(y+7)^2=15^2 is Circle with (a,b)=(15,-7),r=15

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(x-15)^2+(y+7)^2=15^2

(x - 15)^{2} + (y + 7)^{2} = 1 5^{2}

(a, b) = (15, - 7), r = 15

Solution steps

(x - 15)^{2} + (y + 7)^{2} = 1 5^{2}

Rewrite

(x - 15)^{2} + (y + 7)^{2} = 1 5^{2}

in the form of the standard circle equation

(x - 15)^{2} + (y - (- 7))^{2} = 1 5^{2}

Therefore the circle properties are:

(a, b) = (15, - 7), r = 15

x^{2} + y^{2} + 6 x + 8 y - 11 = 0

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x^{(2)} + y^{(2)} + 25 x + 10 y = - 12

x^{2} + y^{2} + 14 x - 20 y + 100 = 0

x^{2} + 6 x + y^{2} - 8 y - 75 = 0

What is (x-15)^2+(y+7)^2=15^2 ?
The solution to (x-15)^2+(y+7)^2=15^2 is Circle with (a,b)=(15,-7),r=15