What is x^2+y^2+14x-20y+100=0 ?

The solution to x^2+y^2+14x-20y+100=0 is Circle with (a,b)=(-7,10),r=7

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x^2+y^2+14x-20y+100=0

x^{2} + y^{2} + 14 x - 20 y + 100 = 0

(a, b) = (- 7, 10), r = 7

Solution steps

x^{2} + y^{2} + 14 x - 20 y + 100 = 0

Rewrite

x^{2} + y^{2} + 14 x - 20 y + 100 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - 10)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 7, 10), r = 7

x^{2} + 6 x + y^{2} - 8 y - 75 = 0

(x + 2)^{2} + (y + 8)^{2} = 100

(x + 1)^{2} + (y + 2)^{2} = 1

(x - 2)^{2} + (y - 0)^{2} = 5^{2}

x^{2} + y^{2} - 8 x - 10 y + 32 = 0

What is x^2+y^2+14x-20y+100=0 ?
The solution to x^2+y^2+14x-20y+100=0 is Circle with (a,b)=(-7,10),r=7