What is x^2+6x+y^2-8y-75=0 ?

The solution to x^2+6x+y^2-8y-75=0 is Circle with (a,b)=(-3,4),r=10

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x^2+6x+y^2-8y-75=0

x^{2} + 6 x + y^{2} - 8 y - 75 = 0

(a, b) = (- 3, 4), r = 10

Solution steps

x^{2} + 6 x + y^{2} - 8 y - 75 = 0

Rewrite

x^{2} + 6 x + y^{2} - 8 y - 75 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 4)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 3, 4), r = 10

(x + 2)^{2} + (y + 8)^{2} = 100

(x + 1)^{2} + (y + 2)^{2} = 1

(x - 2)^{2} + (y - 0)^{2} = 5^{2}

x^{2} + y^{2} - 8 x - 10 y + 32 = 0

(x + 5)^{2} + (y + 1)^{2} = 81

What is x^2+6x+y^2-8y-75=0 ?
The solution to x^2+6x+y^2-8y-75=0 is Circle with (a,b)=(-3,4),r=10