What is (x+2)^2+(y+8)^2=100 ?

The solution to (x+2)^2+(y+8)^2=100 is Circle with (a,b)=(-2,-8),r=10

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(x+2)^2+(y+8)^2=100

(x + 2)^{2} + (y + 8)^{2} = 100

(a, b) = (- 2, - 8), r = 10

Solution steps

(x + 2)^{2} + (y + 8)^{2} = 100

Rewrite

(x + 2)^{2} + (y + 8)^{2} = 100

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 8))^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 8), r = 10

(x + 1)^{2} + (y + 2)^{2} = 1

(x - 2)^{2} + (y - 0)^{2} = 5^{2}

x^{2} + y^{2} - 8 x - 10 y + 32 = 0

(x + 5)^{2} + (y + 1)^{2} = 81

4 x^{2} + 4 z^{2} = 1

What is (x+2)^2+(y+8)^2=100 ?
The solution to (x+2)^2+(y+8)^2=100 is Circle with (a,b)=(-2,-8),r=10