What is (x+5)^2+(y+1)^2=81 ?

The solution to (x+5)^2+(y+1)^2=81 is Circle with (a,b)=(-5,-1),r=9

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(x+5)^2+(y+1)^2=81

(x + 5)^{2} + (y + 1)^{2} = 81

(a, b) = (- 5, - 1), r = 9

Solution steps

(x + 5)^{2} + (y + 1)^{2} = 81

Rewrite

(x + 5)^{2} + (y + 1)^{2} = 81

in the form of the standard circle equation

(x - (- 5))^{2} + (y - (- 1))^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (- 5, - 1), r = 9

4 x^{2} + 4 z^{2} = 1

(x - 2)^{2} + (y - 3)^{2} = 8

(x - 4)^{2} + (y - 4)^{2} = 4

(x - 4)^{2} + (y - 4)^{2} = 6

(x - (- 4))^{2} + (y - 5)^{2} = 42

What is (x+5)^2+(y+1)^2=81 ?
The solution to (x+5)^2+(y+1)^2=81 is Circle with (a,b)=(-5,-1),r=9