What is 4x^2+4z^2=1 ?

The solution to 4x^2+4z^2=1 is Circle with (a,b)=(0,0),r= 1/2

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4x^2+4z^2=1

4 x^{2} + 4 z^{2} = 1

(a, b) = (0, 0), r = \frac{1}{2}

Solution steps

4 x^{2} + 4 z^{2} = 1

Rewrite

4 x^{2} + 4 z^{2} = 1

in the form of the standard circle equation

(x - 0)^{2} + (z - 0)^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = \frac{1}{2}

(x - 2)^{2} + (y - 3)^{2} = 8

(x - 4)^{2} + (y - 4)^{2} = 4

(x - 4)^{2} + (y - 4)^{2} = 6

(x - (- 4))^{2} + (y - 5)^{2} = 42

x^{2} + y^{2} - 5 x - 6 = 0

What is 4x^2+4z^2=1 ?
The solution to 4x^2+4z^2=1 is Circle with (a,b)=(0,0),r= 1/2