What is x^2+y^2-5x-6=0 ?

The solution to x^2+y^2-5x-6=0 is Circle with (a,b)=(5/2 ,0),r= 7/2

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x^2+y^2-5x-6=0

x^{2} + y^{2} - 5 x - 6 = 0

(a, b) = (\frac{5}{2}, 0), r = \frac{7}{2}

Solution steps

x^{2} + y^{2} - 5 x - 6 = 0

Rewrite

x^{2} + y^{2} - 5 x - 6 = 0

in the form of the standard circle equation

(x - \frac{5}{2})^{2} + (y - 0)^{2} = (\frac{7}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{5}{2}, 0), r = \frac{7}{2}

(x + 6)^{2} + y^{2} = 8

(x + 5)^{2} + (y + 1)^{2} = 36

(x + 7)^{2} + (y - 1)^{2} = 225

x^{2} + 14 x + 49 + y^{2} - 14 y + 49 = 49

(x + 1)^{2} + (y - 3)^{2} = 2^{2}

What is x^2+y^2-5x-6=0 ?
The solution to x^2+y^2-5x-6=0 is Circle with (a,b)=(5/2 ,0),r= 7/2