What is x^2+y^2+4x-6y-36=0 ?

The solution to x^2+y^2+4x-6y-36=0 is Circle with (a,b)=(-2,3),r=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2+4x-6y-36=0

x^{2} + y^{2} + 4 x - 6 y - 36 = 0

(a, b) = (- 2, 3), r = 7

Solution steps

x^{2} + y^{2} + 4 x - 6 y - 36 = 0

Rewrite

x^{2} + y^{2} + 4 x - 6 y - 36 = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 3)^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (- 2, 3), r = 7

\frac{x ^{2}}{2} + \frac{y ^{2}}{2} = 1

x^{2} + y^{2} - 34 = 3 x

x^{2} + y^{2} + 10 x - 10 y + 41 = 0

5 x^{2} + x + 5 y^{2} - y - 9 = 0

x^{2} - 4 x + y^{2} - 6 y = 3

What is x^2+y^2+4x-6y-36=0 ?
The solution to x^2+y^2+4x-6y-36=0 is Circle with (a,b)=(-2,3),r=7