What is x^2+y^2-34=3x ?

The solution to x^2+y^2-34=3x is Circle with (a,b)=(3/2 ,0),r=(sqrt(145))/2

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x^2+y^2-34=3x

x^{2} + y^{2} - 34 = 3 x

(a, b) = (\frac{3}{2}, 0), r = \frac{145}{2}

Solution steps

x^{2} + y^{2} - 34 = 3 x

Rewrite

x^{2} + y^{2} - 34 = 3 x

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - 0)^{2} = (\frac{145}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, 0), r = \frac{145}{2}

x^{2} + y^{2} + 10 x - 10 y + 41 = 0

5 x^{2} + x + 5 y^{2} - y - 9 = 0

x^{2} - 4 x + y^{2} - 6 y = 3

(x - 9)^{2} + (y - 2)^{2} = 25

(x + 9)^{2} + (y - 3)^{2} = 80

What is x^2+y^2-34=3x ?
The solution to x^2+y^2-34=3x is Circle with (a,b)=(3/2 ,0),r=(sqrt(145))/2