What is x^2+y^2-12x+8y+47=0 ?

The solution to x^2+y^2-12x+8y+47=0 is Circle with (a,b)=(6,-4),r=sqrt(5)

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x^2+y^2-12x+8y+47=0

x^{2} + y^{2} - 12 x + 8 y + 47 = 0

(a, b) = (6, - 4), r = 5

Solution steps

x^{2} + y^{2} - 12 x + 8 y + 47 = 0

Rewrite

x^{2} + y^{2} - 12 x + 8 y + 47 = 0

in the form of the standard circle equation

(x - 6)^{2} + (y - (- 4))^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (6, - 4), r = 5

(x - 1)^{2} + (y - 2)^{2} = (22)^{2}

x^{2} - 6 x + y^{2} - 4 y = - 9

(x - 10)^{2} + (y - 5)^{2} = 28

f (x) (f (x)) = - x^{2} + 3 x

x^{2} - 6 x + y^{2} - 4 y = - 4

What is x^2+y^2-12x+8y+47=0 ?
The solution to x^2+y^2-12x+8y+47=0 is Circle with (a,b)=(6,-4),r=sqrt(5)