What is (x-(-3))^2+(y-4)^2=5^2 ?

The solution to (x-(-3))^2+(y-4)^2=5^2 is Circle with (a,b)=(-3,4),r=5

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(x-(-3))^2+(y-4)^2=5^2

(x - (- 3))^{2} + (y - 4)^{2} = 5^{2}

(a, b) = (- 3, 4), r = 5

Solution steps

(x - (- 3))^{2} + (y - 4)^{2} = 5^{2}

Rewrite

(x - (- 3))^{2} + (y - 4)^{2} = 5^{2}

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 4)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 3, 4), r = 5

4 x^{2} + 8 x + 4 y^{2} - 12 y = 23

x^{2} + y^{2} + 8 x + 4 y - 5 = 0

x^{2} + y^{2} - 2 x - 15 + 14 y = 0

(x^{2} + 3 x) + (y^{2} - 4 y) = 6

2 x^{2} + 2 y^{2} - 2 x + 4 y = 45

What is (x-(-3))^2+(y-4)^2=5^2 ?
The solution to (x-(-3))^2+(y-4)^2=5^2 is Circle with (a,b)=(-3,4),r=5