What is x^2+y^2+8x+8y=-16 ?

The solution to x^2+y^2+8x+8y=-16 is Circle with (a,b)=(-4,-4),r=4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2+8x+8y=-16

x^{2} + y^{2} + 8 x + 8 y = - 16

(a, b) = (- 4, - 4), r = 4

Solution steps

x^{2} + y^{2} + 8 x + 8 y = - 16

Rewrite

x^{2} + y^{2} + 8 x + 8 y = - 16

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 4))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 4), r = 4

3 x^{2} + 6 y + 3 y^{2} + 5 x - 15 = 0

x^{2} + y^{2} - 2 x + 4 y = 11

x^{2} + y^{2} - x + 3 y - \frac{15}{4} = 0

x^{2} + y^{2} + 6 x - 10 y - 2 = 0

(x + \frac{1}{2})^{2} + (y + 3)^{2} = \frac{1}{2 ^{2}}

What is x^2+y^2+8x+8y=-16 ?
The solution to x^2+y^2+8x+8y=-16 is Circle with (a,b)=(-4,-4),r=4