What is (x^2+(y^2))/(36)=1 ?

The solution to (x^2+(y^2))/(36)=1 is Circle with (a,b)=(0,0),r=6

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(x^2+(y^2))/(36)=1

\frac{x ^{2} + ( y ^{2} )}{36} = 1

(a, b) = (0, 0), r = 6

Solution steps

\frac{x ^{2} + y ^{2}}{36} = 1

Rewrite

\frac{x ^{2} + y ^{2}}{36} = 1

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 6

2 x^{2} + 16 x + 2 y^{2} + 14 y = - \frac{77}{2}

1^{2} = (x - 0)^{2} + (y - 0)^{2}

x^{2} + y^{2} - 4 y - 15 = 6

x^{2} + (y + 1)^{2} = 2^{2}

5 0^{2} = (x - 21.21)^{2} + (y - 21.21)^{2}

What is (x^2+(y^2))/(36)=1 ?
The solution to (x^2+(y^2))/(36)=1 is Circle with (a,b)=(0,0),r=6