What is (x+1)^2+(y+1)^2=6 ?

The solution to (x+1)^2+(y+1)^2=6 is Circle with (a,b)=(-1,-1),r=sqrt(6)

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(x+1)^2+(y+1)^2=6

(x + 1)^{2} + (y + 1)^{2} = 6

(a, b) = (- 1, - 1), r = 6

Solution steps

(x + 1)^{2} + (y + 1)^{2} = 6

Rewrite

(x + 1)^{2} + (y + 1)^{2} = 6

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 1))^{2} = (6)^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 1), r = 6

(x - (- 7))^{2} + (y - (- 4))^{2} = 7^{2}

4 x^{2} + 12 x + 4 y^{2} + 16 y + 11 = 0

(x + 5)^{2} + (y + 6)^{2} = 12

x^{2} + y^{2} - x - y - 16 = 0

(x^{2} + 2 x) + (y^{2} + 4 y) = - 1

What is (x+1)^2+(y+1)^2=6 ?
The solution to (x+1)^2+(y+1)^2=6 is Circle with (a,b)=(-1,-1),r=sqrt(6)