What is x^2+y^2+2-3x+2y-5=0 ?

The solution to x^2+y^2+2-3x+2y-5=0 is Circle with (a,b)=(3/2 ,-1),r= 5/2

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x^2+y^2+2-3x+2y-5=0

x^{2} + y^{2} + 2 - 3 x + 2 y - 5 = 0

(a, b) = (\frac{3}{2}, - 1), r = \frac{5}{2}

Solution steps

x^{2} + y^{2} + 2 - 3 x + 2 y - 5 = 0

Rewrite

x^{2} + y^{2} + 2 - 3 x + 2 y - 5 = 0

in the form of the standard circle equation

(x - \frac{3}{2})^{2} + (y - (- 1))^{2} = (\frac{5}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{3}{2}, - 1), r = \frac{5}{2}

x^{2} + y^{2} - 10 x - 8 y + 5 = 0

x^{2} + y^{2} = 520

0.3 8^{2} = (x + 1.7)^{2} + (y + 0.5)^{2}

4 x^{2} - 4 + 4 y^{2} + 4 y = 9

x^{2} + y^{2} - \frac{3}{2} x + \frac{2}{3} y - \frac{239}{36} = 0

What is x^2+y^2+2-3x+2y-5=0 ?
The solution to x^2+y^2+2-3x+2y-5=0 is Circle with (a,b)=(3/2 ,-1),r= 5/2