What is x^2+y^2=520 ?

The solution to x^2+y^2=520 is Circle with (a,b)=(0,0),r=sqrt(520)

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x^2+y^2=520

x^{2} + y^{2} = 520

(a, b) = (0, 0), r = 520

Solution steps

x^{2} + y^{2} = 520

Rewrite

x^{2} + y^{2} = 520

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (520)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 520

0.3 8^{2} = (x + 1.7)^{2} + (y + 0.5)^{2}

4 x^{2} - 4 + 4 y^{2} + 4 y = 9

x^{2} + y^{2} - \frac{3}{2} x + \frac{2}{3} y - \frac{239}{36} = 0

[x - (- 3)]^{2} + (y - 1)^{2} = 1 0^{2}

x^{2} + y^{2} + 18 x = - 80

What is x^2+y^2=520 ?
The solution to x^2+y^2=520 is Circle with (a,b)=(0,0),r=sqrt(520)