What is (x-2)^2+(y+7)^2=49 ?

The solution to (x-2)^2+(y+7)^2=49 is Circle with (a,b)=(2,-7),r=7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-2)^2+(y+7)^2=49

(x - 2)^{2} + (y + 7)^{2} = 49

(a, b) = (2, - 7), r = 7

Solution steps

(x - 2)^{2} + (y + 7)^{2} = 49

Rewrite

(x - 2)^{2} + (y + 7)^{2} = 49

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 7))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (2, - 7), r = 7

x^{2} + y^{2} + 8 x + 12 y = 0

(x + 3)^{2} + (y - 4)^{2} = 7

(x - 2)^{2} + (y + 2)^{2} = 20

(x - 2)^{2} + (y + 2)^{2} = 25

(x + 1)^{2} + (y - \frac{2}{3})^{2} = \frac{281}{3}^{2}

What is (x-2)^2+(y+7)^2=49 ?
The solution to (x-2)^2+(y+7)^2=49 is Circle with (a,b)=(2,-7),r=7