What is (x-15)^2+(y+15)^2=256 ?

The solution to (x-15)^2+(y+15)^2=256 is Circle with (a,b)=(15,-15),r=16

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(x-15)^2+(y+15)^2=256

(x - 15)^{2} + (y + 15)^{2} = 256

(a, b) = (15, - 15), r = 16

Solution steps

(x - 15)^{2} + (y + 15)^{2} = 256

Rewrite

(x - 15)^{2} + (y + 15)^{2} = 256

in the form of the standard circle equation

(x - 15)^{2} + (y - (- 15))^{2} = 1 6^{2}

Therefore the circle properties are:

(a, b) = (15, - 15), r = 16

[5 (x + 4)]^{2} + 25 (y - 2)^{2} = 625

x^{2} - 1 = 0 - y^{2} + 1

- x^{2} - y^{2} = - 1

- x^{2} - y^{2} + 2 x - 3 y + \frac{3}{4} = 0

(x - 5)^{2} + (y + 2)^{2} = 15

What is (x-15)^2+(y+15)^2=256 ?
The solution to (x-15)^2+(y+15)^2=256 is Circle with (a,b)=(15,-15),r=16