What is (x-5)^2+y^2=1 ?

The solution to (x-5)^2+y^2=1 is Circle with (a,b)=(5,0),r=1

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(x-5)^2+y^2=1

(x - 5)^{2} + y^{2} = 1

(a, b) = (5, 0), r = 1

Solution steps

(x - 5)^{2} + y^{2} = 1

Rewrite

(x - 5)^{2} + y^{2} = 1

in the form of the standard circle equation

(x - 5)^{2} + (y - 0)^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (5, 0), r = 1

y^{2} = 169 - x^{2}

x^{2} + y^{2} = \frac{49}{16}

x^{2} + y^{2} - 12 x + 8 y + 36 = 0

x^{2} + y^{2} + 20 x - 12 y + 72 = 0

(x - 3)^{2} + (y + 2)^{2} + (x - 5)^{2} + (y + 5)^{2} = 16

What is (x-5)^2+y^2=1 ?
The solution to (x-5)^2+y^2=1 is Circle with (a,b)=(5,0),r=1