What is x^2+y^2+20x-12y+72=0 ?

The solution to x^2+y^2+20x-12y+72=0 is Circle with (a,b)=(-10,6),r=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2+20x-12y+72=0

x^{2} + y^{2} + 20 x - 12 y + 72 = 0

(a, b) = (- 10, 6), r = 8

Solution steps

x^{2} + y^{2} + 20 x - 12 y + 72 = 0

Rewrite

x^{2} + y^{2} + 20 x - 12 y + 72 = 0

in the form of the standard circle equation

(x - (- 10))^{2} + (y - 6)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (- 10, 6), r = 8

(x - 3)^{2} + (y + 2)^{2} + (x - 5)^{2} + (y + 5)^{2} = 16

x^{2} + y^{2} - 4 x - 6 x + 10 = 0

(x - 5)^{2} + (y - 4)^{2} = 3

(x + 12)^{2} + (y - 4)^{2} = 25

(x - 6)^{2} + (y - 6)^{2} = 9

What is x^2+y^2+20x-12y+72=0 ?
The solution to x^2+y^2+20x-12y+72=0 is Circle with (a,b)=(-10,6),r=8