What is x^2+y^2-12x+8y+36=0 ?

The solution to x^2+y^2-12x+8y+36=0 is Circle with (a,b)=(6,-4),r=4

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x^2+y^2-12x+8y+36=0

x^{2} + y^{2} - 12 x + 8 y + 36 = 0

(a, b) = (6, - 4), r = 4

Solution steps

x^{2} + y^{2} - 12 x + 8 y + 36 = 0

Rewrite

x^{2} + y^{2} - 12 x + 8 y + 36 = 0

in the form of the standard circle equation

(x - 6)^{2} + (y - (- 4))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (6, - 4), r = 4

x^{2} + y^{2} + 20 x - 12 y + 72 = 0

(x - 3)^{2} + (y + 2)^{2} + (x - 5)^{2} + (y + 5)^{2} = 16

x^{2} + y^{2} - 4 x - 6 x + 10 = 0

(x - 5)^{2} + (y - 4)^{2} = 3

(x + 12)^{2} + (y - 4)^{2} = 25

What is x^2+y^2-12x+8y+36=0 ?
The solution to x^2+y^2-12x+8y+36=0 is Circle with (a,b)=(6,-4),r=4