What is (x-5)^2+(y-4)^2=sqrt(3) ?

The solution to (x-5)^2+(y-4)^2=sqrt(3) is Circle with (a,b)=(5,4),r=sqrt(\sqrt{3)}

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(x-5)^2+(y-4)^2=sqrt(3)

(x - 5)^{2} + (y - 4)^{2} = 3

(a, b) = (5, 4), r = 3

Solution steps

(x - 5)^{2} + (y - 4)^{2} = 3

Rewrite

(x - 5)^{2} + (y - 4)^{2} = 3

in the form of the standard circle equation

(x - 5)^{2} + (y - 4)^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (5, 4), r = 3

(x + 12)^{2} + (y - 4)^{2} = 25

(x - 6)^{2} + (y - 6)^{2} = 9

4 x^{2} + 4 y^{2} = 5

(x + 2)^{2} + (y + 1)^{2} = \frac{13}{2}

3 - y = x^{2} + y^{2}

What is (x-5)^2+(y-4)^2=sqrt(3) ?
The solution to (x-5)^2+(y-4)^2=sqrt(3) is Circle with (a,b)=(5,4),r=sqrt(\sqrt{3)}